\(\int \frac {(a+b x^3)^{8/3}}{c+d x^3} \, dx\) [86]

Optimal result

Integrand size = 21, antiderivative size = 331 \[ \int \frac {\left (a+b x^3\right )^{8/3}}{c+d x^3} \, dx=-\frac {b (6 b c-11 a d) x \left (a+b x^3\right )^{2/3}}{18 d^2}+\frac {b x \left (a+b x^3\right )^{5/3}}{6 d}+\frac {b^{2/3} \left (9 b^2 c^2-24 a b c d+20 a^2 d^2\right ) \arctan \left (\frac {1+\frac {2 \sqrt [3]{b} x}{\sqrt [3]{a+b x^3}}}{\sqrt {3}}\right )}{9 \sqrt {3} d^3}-\frac {(b c-a d)^{8/3} \arctan \left (\frac {1+\frac {2 \sqrt [3]{b c-a d} x}{\sqrt [3]{c} \sqrt [3]{a+b x^3}}}{\sqrt {3}}\right )}{\sqrt {3} c^{2/3} d^3}-\frac {(b c-a d)^{8/3} \log \left (c+d x^3\right )}{6 c^{2/3} d^3}+\frac {(b c-a d)^{8/3} \log \left (\frac {\sqrt [3]{b c-a d} x}{\sqrt [3]{c}}-\sqrt [3]{a+b x^3}\right )}{2 c^{2/3} d^3}-\frac {b^{2/3} \left (9 b^2 c^2-24 a b c d+20 a^2 d^2\right ) \log \left (-\sqrt [3]{b} x+\sqrt [3]{a+b x^3}\right )}{18 d^3} \]

[Out]

-1/18*b*(-11*a*d+6*b*c)*x*(b*x^3+a)^(2/3)/d^2+1/6*b*x*(b*x^3+a)^(5/3)/d-1/6*(-a*d+b*c)^(8/3)*ln(d*x^3+c)/c^(2/
3)/d^3+1/2*(-a*d+b*c)^(8/3)*ln((-a*d+b*c)^(1/3)*x/c^(1/3)-(b*x^3+a)^(1/3))/c^(2/3)/d^3-1/18*b^(2/3)*(20*a^2*d^
2-24*a*b*c*d+9*b^2*c^2)*ln(-b^(1/3)*x+(b*x^3+a)^(1/3))/d^3+1/27*b^(2/3)*(20*a^2*d^2-24*a*b*c*d+9*b^2*c^2)*arct
an(1/3*(1+2*b^(1/3)*x/(b*x^3+a)^(1/3))*3^(1/2))/d^3*3^(1/2)-1/3*(-a*d+b*c)^(8/3)*arctan(1/3*(1+2*(-a*d+b*c)^(1
/3)*x/c^(1/3)/(b*x^3+a)^(1/3))*3^(1/2))/c^(2/3)/d^3*3^(1/2)

Rubi [A] (verified)

Time = 0.31 (sec) , antiderivative size = 331, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.238, Rules used = {427, 542, 544, 245, 384} \[ \int \frac {\left (a+b x^3\right )^{8/3}}{c+d x^3} \, dx=\frac {b^{2/3} \arctan \left (\frac {\frac {2 \sqrt [3]{b} x}{\sqrt [3]{a+b x^3}}+1}{\sqrt {3}}\right ) \left (20 a^2 d^2-24 a b c d+9 b^2 c^2\right )}{9 \sqrt {3} d^3}-\frac {b^{2/3} \left (20 a^2 d^2-24 a b c d+9 b^2 c^2\right ) \log \left (\sqrt [3]{a+b x^3}-\sqrt [3]{b} x\right )}{18 d^3}-\frac {(b c-a d)^{8/3} \arctan \left (\frac {\frac {2 x \sqrt [3]{b c-a d}}{\sqrt [3]{c} \sqrt [3]{a+b x^3}}+1}{\sqrt {3}}\right )}{\sqrt {3} c^{2/3} d^3}-\frac {(b c-a d)^{8/3} \log \left (c+d x^3\right )}{6 c^{2/3} d^3}+\frac {(b c-a d)^{8/3} \log \left (\frac {x \sqrt [3]{b c-a d}}{\sqrt [3]{c}}-\sqrt [3]{a+b x^3}\right )}{2 c^{2/3} d^3}-\frac {b x \left (a+b x^3\right )^{2/3} (6 b c-11 a d)}{18 d^2}+\frac {b x \left (a+b x^3\right )^{5/3}}{6 d} \]

[In]

Int[(a + b*x^3)^(8/3)/(c + d*x^3),x]

[Out]

-1/18*(b*(6*b*c - 11*a*d)*x*(a + b*x^3)^(2/3))/d^2 + (b*x*(a + b*x^3)^(5/3))/(6*d) + (b^(2/3)*(9*b^2*c^2 - 24*
a*b*c*d + 20*a^2*d^2)*ArcTan[(1 + (2*b^(1/3)*x)/(a + b*x^3)^(1/3))/Sqrt[3]])/(9*Sqrt[3]*d^3) - ((b*c - a*d)^(8
/3)*ArcTan[(1 + (2*(b*c - a*d)^(1/3)*x)/(c^(1/3)*(a + b*x^3)^(1/3)))/Sqrt[3]])/(Sqrt[3]*c^(2/3)*d^3) - ((b*c -
a*d)^(8/3)*Log[c + d*x^3])/(6*c^(2/3)*d^3) + ((b*c - a*d)^(8/3)*Log[((b*c - a*d)^(1/3)*x)/c^(1/3) - (a + b*x^
3)^(1/3)])/(2*c^(2/3)*d^3) - (b^(2/3)*(9*b^2*c^2 - 24*a*b*c*d + 20*a^2*d^2)*Log[-(b^(1/3)*x) + (a + b*x^3)^(1/
3)])/(18*d^3)

Rule 245

Int[((a_) + (b_.)*(x_)^3)^(-1/3), x_Symbol] :> Simp[ArcTan[(1 + 2*Rt[b, 3]*(x/(a + b*x^3)^(1/3)))/Sqrt[3]]/(Sq
rt[3]*Rt[b, 3]), x] - Simp[Log[(a + b*x^3)^(1/3) - Rt[b, 3]*x]/(2*Rt[b, 3]), x] /; FreeQ[{a, b}, x]

Rule 384

Int[1/(((a_) + (b_.)*(x_)^3)^(1/3)*((c_) + (d_.)*(x_)^3)), x_Symbol] :> With[{q = Rt[(b*c - a*d)/c, 3]}, Simp[
ArcTan[(1 + (2*q*x)/(a + b*x^3)^(1/3))/Sqrt[3]]/(Sqrt[3]*c*q), x] + (-Simp[Log[q*x - (a + b*x^3)^(1/3)]/(2*c*q
), x] + Simp[Log[c + d*x^3]/(6*c*q), x])] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0]

Rule 427

Int[((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_), x_Symbol] :> Simp[d*x*(a + b*x^n)^(p + 1)*((c
+ d*x^n)^(q - 1)/(b*(n*(p + q) + 1))), x] + Dist[1/(b*(n*(p + q) + 1)), Int[(a + b*x^n)^p*(c + d*x^n)^(q - 2)
*Simp[c*(b*c*(n*(p + q) + 1) - a*d) + d*(b*c*(n*(p + 2*q - 1) + 1) - a*d*(n*(q - 1) + 1))*x^n, x], x], x] /; F
reeQ[{a, b, c, d, n, p}, x] && NeQ[b*c - a*d, 0] && GtQ[q, 1] && NeQ[n*(p + q) + 1, 0] &&  !IGtQ[p, 1] && IntB
inomialQ[a, b, c, d, n, p, q, x]

Rule 542

Int[((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_))^(q_.)*((e_) + (f_.)*(x_)^(n_)), x_Symbol] :> Simp[
f*x*(a + b*x^n)^(p + 1)*((c + d*x^n)^q/(b*(n*(p + q + 1) + 1))), x] + Dist[1/(b*(n*(p + q + 1) + 1)), Int[(a +
b*x^n)^p*(c + d*x^n)^(q - 1)*Simp[c*(b*e - a*f + b*e*n*(p + q + 1)) + (d*(b*e - a*f) + f*n*q*(b*c - a*d) + b*
d*e*n*(p + q + 1))*x^n, x], x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && GtQ[q, 0] && NeQ[n*(p + q + 1) + 1
, 0]

Rule 544

Int[(((a_) + (b_.)*(x_)^(n_))^(p_)*((e_) + (f_.)*(x_)^(n_)))/((c_) + (d_.)*(x_)^(n_)), x_Symbol] :> Dist[f/d,
Int[(a + b*x^n)^p, x], x] + Dist[(d*e - c*f)/d, Int[(a + b*x^n)^p/(c + d*x^n), x], x] /; FreeQ[{a, b, c, d, e,
f, p, n}, x]

Rubi steps \begin{align*} \text {integral}& = \frac {b x \left (a+b x^3\right )^{5/3}}{6 d}+\frac {\int \frac {\left (a+b x^3\right )^{2/3} \left (-a (b c-6 a d)-b (6 b c-11 a d) x^3\right )}{c+d x^3} \, dx}{6 d} \\ & = -\frac {b (6 b c-11 a d) x \left (a+b x^3\right )^{2/3}}{18 d^2}+\frac {b x \left (a+b x^3\right )^{5/3}}{6 d}+\frac {\int \frac {2 a \left (3 b^2 c^2-7 a b c d+9 a^2 d^2\right )+2 b \left (9 b^2 c^2-24 a b c d+20 a^2 d^2\right ) x^3}{\sqrt [3]{a+b x^3} \left (c+d x^3\right )} \, dx}{18 d^2} \\ & = -\frac {b (6 b c-11 a d) x \left (a+b x^3\right )^{2/3}}{18 d^2}+\frac {b x \left (a+b x^3\right )^{5/3}}{6 d}-\frac {(b c-a d)^3 \int \frac {1}{\sqrt [3]{a+b x^3} \left (c+d x^3\right )} \, dx}{d^3}+\frac {\left (b \left (9 b^2 c^2-24 a b c d+20 a^2 d^2\right )\right ) \int \frac {1}{\sqrt [3]{a+b x^3}} \, dx}{9 d^3} \\ & = -\frac {b (6 b c-11 a d) x \left (a+b x^3\right )^{2/3}}{18 d^2}+\frac {b x \left (a+b x^3\right )^{5/3}}{6 d}+\frac {b^{2/3} \left (9 b^2 c^2-24 a b c d+20 a^2 d^2\right ) \tan ^{-1}\left (\frac {1+\frac {2 \sqrt [3]{b} x}{\sqrt [3]{a+b x^3}}}{\sqrt {3}}\right )}{9 \sqrt {3} d^3}-\frac {(b c-a d)^{8/3} \tan ^{-1}\left (\frac {1+\frac {2 \sqrt [3]{b c-a d} x}{\sqrt [3]{c} \sqrt [3]{a+b x^3}}}{\sqrt {3}}\right )}{\sqrt {3} c^{2/3} d^3}-\frac {(b c-a d)^{8/3} \log \left (c+d x^3\right )}{6 c^{2/3} d^3}+\frac {(b c-a d)^{8/3} \log \left (\frac {\sqrt [3]{b c-a d} x}{\sqrt [3]{c}}-\sqrt [3]{a+b x^3}\right )}{2 c^{2/3} d^3}-\frac {b^{2/3} \left (9 b^2 c^2-24 a b c d+20 a^2 d^2\right ) \log \left (-\sqrt [3]{b} x+\sqrt [3]{a+b x^3}\right )}{18 d^3} \\ \end{align*}

Mathematica [C] (warning: unable to verify)

Result contains higher order function than in optimal. Order 6 vs. order 3 in optimal.

Time = 10.83 (sec) , antiderivative size = 655, normalized size of antiderivative = 1.98 \[ \int \frac {\left (a+b x^3\right )^{8/3}}{c+d x^3} \, dx=\frac {3 b \sqrt [3]{b c-a d} \left (9 b^2 c^2-24 a b c d+20 a^2 d^2\right ) x^4 \sqrt [3]{1+\frac {b x^3}{a}} \operatorname {AppellF1}\left (\frac {4}{3},\frac {1}{3},1,\frac {7}{3},-\frac {b x^3}{a},-\frac {d x^3}{c}\right )+2 \sqrt [3]{c} \left (-18 a b^2 c^{5/3} \sqrt [3]{b c-a d} x+42 a^2 b c^{2/3} d \sqrt [3]{b c-a d} x-18 b^3 c^{5/3} \sqrt [3]{b c-a d} x^4+51 a b^2 c^{2/3} d \sqrt [3]{b c-a d} x^4+9 b^3 c^{2/3} d \sqrt [3]{b c-a d} x^7+2 \sqrt {3} a \left (3 b^2 c^2-7 a b c d+9 a^2 d^2\right ) \sqrt [3]{a+b x^3} \arctan \left (\frac {1+\frac {2 \sqrt [3]{b c-a d} x}{\sqrt [3]{c} \sqrt [3]{b+a x^3}}}{\sqrt {3}}\right )-2 a \left (3 b^2 c^2-7 a b c d+9 a^2 d^2\right ) \sqrt [3]{a+b x^3} \log \left (\sqrt [3]{c}-\frac {\sqrt [3]{b c-a d} x}{\sqrt [3]{b+a x^3}}\right )+3 a b^2 c^2 \sqrt [3]{a+b x^3} \log \left (c^{2/3}+\frac {(b c-a d)^{2/3} x^2}{\left (b+a x^3\right )^{2/3}}+\frac {\sqrt [3]{c} \sqrt [3]{b c-a d} x}{\sqrt [3]{b+a x^3}}\right )-7 a^2 b c d \sqrt [3]{a+b x^3} \log \left (c^{2/3}+\frac {(b c-a d)^{2/3} x^2}{\left (b+a x^3\right )^{2/3}}+\frac {\sqrt [3]{c} \sqrt [3]{b c-a d} x}{\sqrt [3]{b+a x^3}}\right )+9 a^3 d^2 \sqrt [3]{a+b x^3} \log \left (c^{2/3}+\frac {(b c-a d)^{2/3} x^2}{\left (b+a x^3\right )^{2/3}}+\frac {\sqrt [3]{c} \sqrt [3]{b c-a d} x}{\sqrt [3]{b+a x^3}}\right )\right )}{108 c d^2 \sqrt [3]{b c-a d} \sqrt [3]{a+b x^3}} \]

[In]

Integrate[(a + b*x^3)^(8/3)/(c + d*x^3),x]

[Out]

(3*b*(b*c - a*d)^(1/3)*(9*b^2*c^2 - 24*a*b*c*d + 20*a^2*d^2)*x^4*(1 + (b*x^3)/a)^(1/3)*AppellF1[4/3, 1/3, 1, 7
/3, -((b*x^3)/a), -((d*x^3)/c)] + 2*c^(1/3)*(-18*a*b^2*c^(5/3)*(b*c - a*d)^(1/3)*x + 42*a^2*b*c^(2/3)*d*(b*c -
a*d)^(1/3)*x - 18*b^3*c^(5/3)*(b*c - a*d)^(1/3)*x^4 + 51*a*b^2*c^(2/3)*d*(b*c - a*d)^(1/3)*x^4 + 9*b^3*c^(2/3
)*d*(b*c - a*d)^(1/3)*x^7 + 2*Sqrt[3]*a*(3*b^2*c^2 - 7*a*b*c*d + 9*a^2*d^2)*(a + b*x^3)^(1/3)*ArcTan[(1 + (2*(
b*c - a*d)^(1/3)*x)/(c^(1/3)*(b + a*x^3)^(1/3)))/Sqrt[3]] - 2*a*(3*b^2*c^2 - 7*a*b*c*d + 9*a^2*d^2)*(a + b*x^3
)^(1/3)*Log[c^(1/3) - ((b*c - a*d)^(1/3)*x)/(b + a*x^3)^(1/3)] + 3*a*b^2*c^2*(a + b*x^3)^(1/3)*Log[c^(2/3) + (
(b*c - a*d)^(2/3)*x^2)/(b + a*x^3)^(2/3) + (c^(1/3)*(b*c - a*d)^(1/3)*x)/(b + a*x^3)^(1/3)] - 7*a^2*b*c*d*(a +
b*x^3)^(1/3)*Log[c^(2/3) + ((b*c - a*d)^(2/3)*x^2)/(b + a*x^3)^(2/3) + (c^(1/3)*(b*c - a*d)^(1/3)*x)/(b + a*x
^3)^(1/3)] + 9*a^3*d^2*(a + b*x^3)^(1/3)*Log[c^(2/3) + ((b*c - a*d)^(2/3)*x^2)/(b + a*x^3)^(2/3) + (c^(1/3)*(b
*c - a*d)^(1/3)*x)/(b + a*x^3)^(1/3)]))/(108*c*d^2*(b*c - a*d)^(1/3)*(a + b*x^3)^(1/3))

Maple [A] (verified)

Time = 6.92 (sec) , antiderivative size = 461, normalized size of antiderivative = 1.39

method	result	size
pseudoelliptic	\(-\frac {\frac {\left (a d -b c \right )^{3} \ln \left (\frac {\left (\frac {a d -b c}{c}\right )^{\frac {2}{3}} x^{2}-\left (\frac {a d -b c}{c}\right )^{\frac {1}{3}} \left (b \,x^{3}+a \right )^{\frac {1}{3}} x +\left (b \,x^{3}+a \right )^{\frac {2}{3}}}{x^{2}}\right )}{2}-\frac {\left (\frac {20 a^{2} d^{2} b^{\frac {2}{3}}}{9}+b^{\frac {5}{3}} c \left (b c -\frac {8 a d}{3}\right )\right ) c \left (\frac {a d -b c}{c}\right )^{\frac {1}{3}} \ln \left (\frac {b^{\frac {2}{3}} x^{2}+b^{\frac {1}{3}} \left (b \,x^{3}+a \right )^{\frac {1}{3}} x +\left (b \,x^{3}+a \right )^{\frac {2}{3}}}{x^{2}}\right )}{2}-\left (a d -b c \right )^{3} \ln \left (\frac {\left (\frac {a d -b c}{c}\right )^{\frac {1}{3}} x +\left (b \,x^{3}+a \right )^{\frac {1}{3}}}{x}\right )+\left (\frac {20 a^{2} d^{2} b^{\frac {2}{3}}}{9}+b^{\frac {5}{3}} c \left (b c -\frac {8 a d}{3}\right )\right ) \sqrt {3}\, c \left (\frac {a d -b c}{c}\right )^{\frac {1}{3}} \arctan \left (\frac {\sqrt {3}\, \left (b^{\frac {1}{3}} x +2 \left (b \,x^{3}+a \right )^{\frac {1}{3}}\right )}{3 b^{\frac {1}{3}} x}\right )+\left (\frac {20 a^{2} d^{2} b^{\frac {2}{3}}}{9}+b^{\frac {5}{3}} c \left (b c -\frac {8 a d}{3}\right )\right ) c \left (\frac {a d -b c}{c}\right )^{\frac {1}{3}} \ln \left (\frac {-b^{\frac {1}{3}} x +\left (b \,x^{3}+a \right )^{\frac {1}{3}}}{x}\right )-\frac {7 x b d \left (-\frac {3 b c}{7}+d \left (\frac {3 b \,x^{3}}{14}+a \right )\right ) c \left (b \,x^{3}+a \right )^{\frac {2}{3}} \left (\frac {a d -b c}{c}\right )^{\frac {1}{3}}}{3}-\sqrt {3}\, \arctan \left (\frac {\sqrt {3}\, \left (\left (\frac {a d -b c}{c}\right )^{\frac {1}{3}} x -2 \left (b \,x^{3}+a \right )^{\frac {1}{3}}\right )}{3 \left (\frac {a d -b c}{c}\right )^{\frac {1}{3}} x}\right ) \left (a d -b c \right )^{3}}{3 \left (\frac {a d -b c}{c}\right )^{\frac {1}{3}} c \,d^{3}}\)	\(461\)

[In]

int((b*x^3+a)^(8/3)/(d*x^3+c),x,method=_RETURNVERBOSE)

[Out]

-1/3/((a*d-b*c)/c)^(1/3)*(1/2*(a*d-b*c)^3*ln((((a*d-b*c)/c)^(2/3)*x^2-((a*d-b*c)/c)^(1/3)*(b*x^3+a)^(1/3)*x+(b
*x^3+a)^(2/3))/x^2)-1/2*(20/9*a^2*d^2*b^(2/3)+b^(5/3)*c*(b*c-8/3*a*d))*c*((a*d-b*c)/c)^(1/3)*ln((b^(2/3)*x^2+b
^(1/3)*(b*x^3+a)^(1/3)*x+(b*x^3+a)^(2/3))/x^2)-(a*d-b*c)^3*ln((((a*d-b*c)/c)^(1/3)*x+(b*x^3+a)^(1/3))/x)+(20/9
*a^2*d^2*b^(2/3)+b^(5/3)*c*(b*c-8/3*a*d))*3^(1/2)*c*((a*d-b*c)/c)^(1/3)*arctan(1/3*3^(1/2)*(b^(1/3)*x+2*(b*x^3
+a)^(1/3))/b^(1/3)/x)+(20/9*a^2*d^2*b^(2/3)+b^(5/3)*c*(b*c-8/3*a*d))*c*((a*d-b*c)/c)^(1/3)*ln((-b^(1/3)*x+(b*x
^3+a)^(1/3))/x)-7/3*x*b*d*(-3/7*b*c+d*(3/14*b*x^3+a))*c*(b*x^3+a)^(2/3)*((a*d-b*c)/c)^(1/3)-3^(1/2)*arctan(1/3
*3^(1/2)*(((a*d-b*c)/c)^(1/3)*x-2*(b*x^3+a)^(1/3))/((a*d-b*c)/c)^(1/3)/x)*(a*d-b*c)^3)/c/d^3

Fricas [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 643 vs. \(2 (273) = 546\).

Time = 6.48 (sec) , antiderivative size = 643, normalized size of antiderivative = 1.94 \[ \int \frac {\left (a+b x^3\right )^{8/3}}{c+d x^3} \, dx=-\frac {18 \, \sqrt {3} {\left (b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}\right )} \left (\frac {b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}}{c^{2}}\right )^{\frac {1}{3}} \arctan \left (-\frac {\sqrt {3} {\left (b c - a d\right )} x + 2 \, \sqrt {3} {\left (b x^{3} + a\right )}^{\frac {1}{3}} c \left (\frac {b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}}{c^{2}}\right )^{\frac {1}{3}}}{3 \, {\left (b c - a d\right )} x}\right ) + 2 \, \sqrt {3} {\left (9 \, b^{2} c^{2} - 24 \, a b c d + 20 \, a^{2} d^{2}\right )} \left (-b^{2}\right )^{\frac {1}{3}} \arctan \left (-\frac {\sqrt {3} b x - 2 \, \sqrt {3} {\left (b x^{3} + a\right )}^{\frac {1}{3}} \left (-b^{2}\right )^{\frac {1}{3}}}{3 \, b x}\right ) - 18 \, {\left (b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}\right )} \left (\frac {b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}}{c^{2}}\right )^{\frac {1}{3}} \log \left (\frac {c x \left (\frac {b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}}{c^{2}}\right )^{\frac {2}{3}} - {\left (b x^{3} + a\right )}^{\frac {1}{3}} {\left (b c - a d\right )}}{x}\right ) - 2 \, {\left (9 \, b^{2} c^{2} - 24 \, a b c d + 20 \, a^{2} d^{2}\right )} \left (-b^{2}\right )^{\frac {1}{3}} \log \left (-\frac {\left (-b^{2}\right )^{\frac {2}{3}} x - {\left (b x^{3} + a\right )}^{\frac {1}{3}} b}{x}\right ) + {\left (9 \, b^{2} c^{2} - 24 \, a b c d + 20 \, a^{2} d^{2}\right )} \left (-b^{2}\right )^{\frac {1}{3}} \log \left (-\frac {\left (-b^{2}\right )^{\frac {1}{3}} b x^{2} - {\left (b x^{3} + a\right )}^{\frac {1}{3}} \left (-b^{2}\right )^{\frac {2}{3}} x - {\left (b x^{3} + a\right )}^{\frac {2}{3}} b}{x^{2}}\right ) + 9 \, {\left (b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}\right )} \left (\frac {b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}}{c^{2}}\right )^{\frac {1}{3}} \log \left (-\frac {{\left (b c - a d\right )} x^{2} \left (\frac {b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}}{c^{2}}\right )^{\frac {1}{3}} + {\left (b x^{3} + a\right )}^{\frac {1}{3}} c x \left (\frac {b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}}{c^{2}}\right )^{\frac {2}{3}} + {\left (b x^{3} + a\right )}^{\frac {2}{3}} {\left (b c - a d\right )}}{x^{2}}\right ) - 3 \, {\left (3 \, b^{2} d^{2} x^{4} - 2 \, {\left (3 \, b^{2} c d - 7 \, a b d^{2}\right )} x\right )} {\left (b x^{3} + a\right )}^{\frac {2}{3}}}{54 \, d^{3}} \]

[In]

integrate((b*x^3+a)^(8/3)/(d*x^3+c),x, algorithm="fricas")

[Out]

-1/54*(18*sqrt(3)*(b^2*c^2 - 2*a*b*c*d + a^2*d^2)*((b^2*c^2 - 2*a*b*c*d + a^2*d^2)/c^2)^(1/3)*arctan(-1/3*(sqr
t(3)*(b*c - a*d)*x + 2*sqrt(3)*(b*x^3 + a)^(1/3)*c*((b^2*c^2 - 2*a*b*c*d + a^2*d^2)/c^2)^(1/3))/((b*c - a*d)*x
)) + 2*sqrt(3)*(9*b^2*c^2 - 24*a*b*c*d + 20*a^2*d^2)*(-b^2)^(1/3)*arctan(-1/3*(sqrt(3)*b*x - 2*sqrt(3)*(b*x^3
+ a)^(1/3)*(-b^2)^(1/3))/(b*x)) - 18*(b^2*c^2 - 2*a*b*c*d + a^2*d^2)*((b^2*c^2 - 2*a*b*c*d + a^2*d^2)/c^2)^(1/
3)*log((c*x*((b^2*c^2 - 2*a*b*c*d + a^2*d^2)/c^2)^(2/3) - (b*x^3 + a)^(1/3)*(b*c - a*d))/x) - 2*(9*b^2*c^2 - 2
4*a*b*c*d + 20*a^2*d^2)*(-b^2)^(1/3)*log(-((-b^2)^(2/3)*x - (b*x^3 + a)^(1/3)*b)/x) + (9*b^2*c^2 - 24*a*b*c*d
+ 20*a^2*d^2)*(-b^2)^(1/3)*log(-((-b^2)^(1/3)*b*x^2 - (b*x^3 + a)^(1/3)*(-b^2)^(2/3)*x - (b*x^3 + a)^(2/3)*b)/
x^2) + 9*(b^2*c^2 - 2*a*b*c*d + a^2*d^2)*((b^2*c^2 - 2*a*b*c*d + a^2*d^2)/c^2)^(1/3)*log(-((b*c - a*d)*x^2*((b
^2*c^2 - 2*a*b*c*d + a^2*d^2)/c^2)^(1/3) + (b*x^3 + a)^(1/3)*c*x*((b^2*c^2 - 2*a*b*c*d + a^2*d^2)/c^2)^(2/3) +
(b*x^3 + a)^(2/3)*(b*c - a*d))/x^2) - 3*(3*b^2*d^2*x^4 - 2*(3*b^2*c*d - 7*a*b*d^2)*x)*(b*x^3 + a)^(2/3))/d^3

Sympy [F]

\[ \int \frac {\left (a+b x^3\right )^{8/3}}{c+d x^3} \, dx=\int \frac {\left (a + b x^{3}\right )^{\frac {8}{3}}}{c + d x^{3}}\, dx \]

[In]

integrate((b*x**3+a)**(8/3)/(d*x**3+c),x)

[Out]

Integral((a + b*x**3)**(8/3)/(c + d*x**3), x)

Maxima [F]

\[ \int \frac {\left (a+b x^3\right )^{8/3}}{c+d x^3} \, dx=\int { \frac {{\left (b x^{3} + a\right )}^{\frac {8}{3}}}{d x^{3} + c} \,d x } \]

[In]

integrate((b*x^3+a)^(8/3)/(d*x^3+c),x, algorithm="maxima")

[Out]

integrate((b*x^3 + a)^(8/3)/(d*x^3 + c), x)

Giac [F]

\[ \int \frac {\left (a+b x^3\right )^{8/3}}{c+d x^3} \, dx=\int { \frac {{\left (b x^{3} + a\right )}^{\frac {8}{3}}}{d x^{3} + c} \,d x } \]

[In]

integrate((b*x^3+a)^(8/3)/(d*x^3+c),x, algorithm="giac")

[Out]

integrate((b*x^3 + a)^(8/3)/(d*x^3 + c), x)

Mupad [F(-1)]

Timed out. \[ \int \frac {\left (a+b x^3\right )^{8/3}}{c+d x^3} \, dx=\int \frac {{\left (b\,x^3+a\right )}^{8/3}}{d\,x^3+c} \,d x \]

[In]

int((a + b*x^3)^(8/3)/(c + d*x^3),x)

[Out]

int((a + b*x^3)^(8/3)/(c + d*x^3), x)